lgx+[5(x+1)]=2

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Solution for lgx+[5(x+1)]=2 equation:


Simplifying
lgx + [5(x + 1)] = 2

Reorder the terms:
glx + [5(1 + x)] = 2
glx + [(1 * 5 + x * 5)] = 2
glx + [(5 + 5x)] = 2
glx + [5 + 5x] = 2

Remove brackets around [5 + 5x]
glx + 5 + 5x = 2

Reorder the terms:
5 + glx + 5x = 2

Solving
5 + glx + 5x = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + glx + -5 + 5x = 2 + -5

Reorder the terms:
5 + -5 + glx + 5x = 2 + -5

Combine like terms: 5 + -5 = 0
0 + glx + 5x = 2 + -5
glx + 5x = 2 + -5

Combine like terms: 2 + -5 = -3
glx + 5x = -3

Add '-5x' to each side of the equation.
glx + 5x + -5x = -3 + -5x

Combine like terms: 5x + -5x = 0
glx + 0 = -3 + -5x
glx = -3 + -5x

Divide each side by 'lx'.
g = -3l-1x-1 + -5l-1

Simplifying
g = -3l-1x-1 + -5l-1

Reorder the terms:
g = -5l-1 + -3l-1x-1

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